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Question 2 4/4 pts A bull might be a carrier of osteopetrosis (marble bone disea

ID: 191388 • Letter: Q

Question

Question 2 4/4 pts A bull might be a carrier of osteopetrosis (marble bone disease, assume two alleles in this locus), a recessive lethal condition. Twenty percent of all cows in the same heard are thought to be carriers of the osteopetrosis allele. Artificial insemination matings to randomly chosen cows have already produced 100 normal calves, and no homozygous recessive calves. What is your level of confidence that the bull is not a carrier of the gene for osteopetrosis? 99.41% (You may reach a slightly different number due to rounding) Answer 1: 99.41%

Explanation / Answer

Let us consider the gene for osteoporosis to be “a”

If the bull is a carrier then gene Aa

Lethal condition (dead) aa

We know that

20% of cows are carriers (Aa)

=>20/100 = 1/5 =0.2 of Cows are carriers(Aa)

                 Bull                          Cow

                 Aa                             Aa

F1                AA         Aa     Aa          aa

                                                         (lethal)

Then 1/5 * ¼ = 1/20= 0.05 of the calf would have been dead due to lethal condition i.e on random mating 1 out of 20 calf produced would have been dead but no dead calf has been produced only 100 normal calves are produced so most probably the Bull is not a carrier but homozygous dominant AA.

                 Bull                          Cow

                 AA                           Aa

F1                AA      Aa     AA       Aa (no lethal condition)

Level of confidence is the probability that the gene to occur as we know there is always a probability of minimum error of 0.005 and nothing is absolute or 100% correct in genetics so as per statistical rules

(1-)100 gives the probability in %

(1-0.005)100=99.5%

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