10. Considering question 9 again, what is the probability of producing a pink ey

Question

10. Considering question 9 again, what is the probability of producing a pink eyed, straight winged flea in the F2 generation? 10 a. 9/16 b. 9/32 C. 1/8 d. 1/16 e. 1/32 11. What is the probability of a family of 6 consisting of 4 girls and 2 boys? a. 10/128 b. 15/64 /64 d. 1/256,il e. 15/32 42] [.hth] A.,½fa 12. In humans, albino individuals are homozygous recessive for an autosomal gene. If two normal parents have an albino daughter and a normal son. What is the probability that their son is homozygous? a. 1/4 b. 1/2 c. 1/8 d. 2/3 e. 1/32 12 13. Referring to question 12, what is the probability that the father is heterozygous? a. 1/4 b. 1/2 c. 1 13. 14. Again referring to question 12, what is the probability that out of 4 children, 2 are albino? a. 1/256 b.67/256 c.5/24 d. 54/256 e.54/128 14 15. Again referring to question 12, what is the probability that out of 4 children, 2 or more are albino? a. 1/256 b.67/256 c:5/24d. 54/256 e. 54/128 15.

Explanation / Answer

using binomial expression of probability,P= (n! / x!(n-x)!) p^x *q^(n-x)

ans 11-probability of family of 6 consisting of 4 girls and 2 boys-

probability of girl (p) =1/2, probability of boy (q)=1/2

total no. of individual=6,   no. of girl (x)=4, no. of boy(n-x)=2

P=(6!/4! 2!) (1/2)^4 (1/2)^2 =15/64

option b is correct

ans 12- albinism is autosomal recessive condition, so genotype of albino will be aa & probability will be 1/4

because parents are normal but daughter is albino,it means both parents are heterozygous. so the probability of a normal homozygous son will be 1/4 option (a)

ans 13- probability of father being heterozygous will be 1 because it is recessive autosomal disease & one child is diseased. option c

ans 14- total child n=4, albino child x=2, n-x=2

probability of albino p =1/4, probability of normal q = 3/4, USING BINOMIAL EXPRESSION

P=27/128 =54/256 option d is correct

ans 15- probability of 2 are albino + P of 3 are albino + P of 4 are albino

(54/256) + (3/64) + (1/256) = 67/256 option b is correct

parent A a A AA Aa a Aa aa

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