How do you relate rate of photosynthesis to oxidized DCPIP concentration? In the

Question

How do you relate rate of photosynthesis to oxidized DCPIP concentration? In the photosynthesis experiment, you monitor the rate of electron transport as absorbance of oxidized DCPIP versus time. If you want to compare the actual rate across different variables (i.e. light intensity) then you need to convert absorbance to a more meaningful and quantifiable value such as concentration Based on the Beer-Lambert law, A-C (refer to the Bio 204 Lab Manual), so we can make a standard curve that relates the absorbance of (oxidized) DCPIP to known concentrations of (oxidized) DCPIP. We use that curve to convert from absorbance to concentration Complete the table by calculating the final concentration of (oxidized) DCPIP using C1V1-C2V How will you prepare the blank? Complete the volumes for the Blank in the table Tube Volume (m) of Volume (ml) of 0.2M (ox.) DCPIP Volume (ml) Water Volume (ml) Total Final Concentration Dilution factor 0.2M NaP 6.5 Buffer (ox.) DCPIP (uM) initial 1.04 0.782 0.52 0.347 0.26 0.13 0.104 0.052 0.875 0.875 0.875 0.875 0.875 0.875 0.875 0.875 3.085 3.343 3.605 3.778 3.865 3.995 4.021 4.073 5.0 5.0 5.0 5.0 5.0 5.0 5.0 5.0 5.0 41.6 1.33 31.3 4 4 20 Blank

Explanation / Answer

Answers

3. C1V1 = c2V2

0.52 X 0.2 X 10-3 = 5 X C2

C2 = 0.0208 mM

C2 = 0.0208 X 1000 = 20.8 uM (1000 mulitiply for converting mM to uM)

Like this we need to solve the others,

4. 13.9 uM
5. 10.4 uM
6. 5.2 uM
7. 4.1 uM
8. 2 uM

Blank - We only have Water 5ml in blank solution.

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