A 1.15-kg grinding wheel 22.0 cm in diameter is spinning counterclockwise at a r

Question

A 1.15-kg grinding wheel 22.0 cm in diameter is spinning counterclockwise at a rate of 20.0 revolutions per second. when the power to the grinder is turned off, the grinding wheel shows with constant angular acceleration and takes 80.0 s to come to the rest.a) what was the angular acceleration in (rad/s^2) of the grinding wheel as it came to the rest if we take a counterclockwise rotation as positive? b) how many revolutions did the wheel make during the time it was coming to rest ? full steps plz

Explanation / Answer

m = 1.15 kg r = 0.11 m w = 2 * pi * n = 40 pi rad/s a = -w/t = -1.57 rad / s^2 b ) s = ut + 0.5*a*t^2 = 5026.55 radians = 5026.55 / 2 * pi = 800 revolutions

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