In a RLC circuit , R = 150 Ohms, L = 500mH, and C is to be determined. If an AC

Question

In a RLC circuit , R = 150 Ohms, L = 500mH, and C is to be determined. If an AC signal with a frequency of 60 Hz and rms voltage of 110V is connected to the circuit, the rms is measured to be 0.600 A. Find the impedance of the circuit, find the inductive reactance of the inductor, find the rms voltage across the inductor, find the capacitance and the capacitive reactance, find the average power dissipated by the resistor, at what frequency will this circuit have resonance? Find the phasor angle between the voltage and current in the circuit.

Explanation / Answer

a)total impedance

Z=Vrms/Irms =110/0.6 =183.33

b)Inductive reactance

XL =2fL =2*60*500*10-3 =188.5

rms voltage across inductor

VL =IXL =0.6*188.5 =113.1V

c)Z=[R2+(XL-XC)2]=183.33

1502+(188.5-XC)2=183.332

(188.5-XC)2=11,111.1

188.5-XC =105.4

capacitive reactance

XC=83.1

capacitance C=1/2fXC

C=1/2*60*83.1 =3.19*10-5F 32F

d)average power dissipated by resistor

P=Irms2R =0.62*150 =54 watts

e)resonant frequency

fr=1/2(LC)=1/2(500*10-3*32*10-6)

fr=39.8Hz

f) =tan-1(X/R)

=tan-1(188.5-83.1/150)

=35.10

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.