A 1.10 m long straight wire section has a resistance R = 39.0 ohm and is connect

Question

A 1.10 m long straight wire section has a resistance R = 39.0 ohm and is connected, with conducting wire of negligible resistance, to a 9.00 V battery. The wire is located in a uniform magnetic field B directed perpendicular to that section of wire. Calculate the magnitude of B when the force on the wire due to B has a magnitude of 0.150 N.

Explanation / Answer

The Force on a current carrying conductor in a Magnetic Field is given by F = ILB sin@ inthis case @ = 90 (perpendicular to wire) --> sin 90 = 1 so F = ILB current I = V/R = 9/39 = 0.23A we need B make it subject of expression B = F/IL B = 0.150/(0.23 x 1.10) B = 0.6 T (T is Tesla Units for B)

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