SHOW MATHEMATICAL WORK IN THE SPACES BELOVw Problem sets: 9. Calculate the numbe

Question

SHOW MATHEMATICAL WORK IN THE SPACES BELOVw Problem sets: 9. Calculate the number of each genotype in a Hardy-Weinberg equailäbrium population of 4780 individuals with a T allele frequency of 0.75; write the number of each genotype in the spaces below: No. TT No. Tt- No, tt 10. Consider an initial population of 615 Gg individuals, 375 Gg individuals, and 82 gg individuals are the Frequency of A Frequency of a b. Given the allele frequencies you calculated above, determine the actual numbers of each of the genotypes you would expect based on the allele frequencies calculated No. GG

Explanation / Answer

1- According to Hardy-Weinberg Equilibrium allelic and genotypic frequency is always equal to 1

Given that frequency of T allele is 0.75

SInce p+q =1

Here p = T

and q= t

So, frequency of t = 1-0.75 = 0.25

Genotypic frequency can find out by using

T2 +2Tt +t2 =1

0.75 *0.75 + 2*0.75*0.25 + 0.25*0.25= 1

0.5625 + 0.375 + 0.0625 = 1

So frequency of TT is 0.5625

Frequecy of Tt 0.375

And frequency of tt is 0.0625

Number of individual having TT allele is 0.5625 * 4780 = 2689

Number of individual having Tt allele is 0.375 * 4780 = 1792

Number of individual having tt allele is 0.0625 * 4780 = 299

2-

b- Total number of individaul = 1072

Frequency of GG = 615/1072 = 0.5736

Frequency of Gg = 375/1072 = 0.3498

Frequency of gg = 82/1072 = 0.0764

a- Frequency of A = square root of frenqency of genotype GG = square root of 0.5736 = 0.75

Freuqncy of a= Square root of frequency of genotype gg = square root of gg = 0.064 = 0.25

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.