A heavy-duty stapling gun uses a 0.153 kg metal rod that rams against the staple

Question

A heavy-duty stapling gun uses a 0.153 kg metal rod that rams against the staple to eject it. The rod is pushed by a stiff spring called a "ram spring" (k = 35390 N/m). The mass of this spring may be ignored. Squeezing the handle of the gun first compresses the ram spring by 3.10 10-2 m from its unstrained length and then releases it. Assuming that the ram spring is oriented vertically and is still compressed by 5.80 10-3 m when the downward-moving ram hits the staple, find the speed of the ram at the instant of contact.

Explanation / Answer

The energy released by the spring is Es =

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