Question 1. (8 pts). Consider that the following double stranded DNA is your gen
ID: 190998 • Letter: Q
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Question 1. (8 pts). Consider that the following double stranded DNA is your gene of interest. Please indicate the mRNA sequence that will be generated after transcription of your gene and the polypeptide generated after translation. Use the bottom strand as your template strand. Label the 5' and 3' of the mRNA and the amino (N") and carboxyl (C") ends of the polypeptide. Use the genetic code table to generate your polypeptide (page 108 of text). 5' CGCTATGAATCCAATCAAGCATGAATAGTTT 3' 3' GCGATACTTAGGTTAGTTCGTACTTATCAAA 5' DNA a. (1 pt) mRNA: b. 1 pt) polypeptide: c. (1 pt) What is the sequence of bases of the anticodon (indicate 5' and 3 ends of the anticodon) for the third amino acid of that polypeptide? d. 1 pt) How many codons are used to produce that polypeptide 2 Mark them in your mRNA strand e. (1 pt) How many anticodons are used to produce that polypeptide? f. (1 pt) Mark the 5'UTR sequence in the GIVEN DNA g. (1 pt) Mark the 3 UTR sequence in the GIVEN DNA h. (1 pt) How many tRNAsl be used to make this polypeptide?Explanation / Answer
A gene is the sequence of DNA which codes for a molecule. Transcription is the first step of gene expression. A segment of DNA is transcribed into mRNA.
RNA polymerase is the enzyme which catalyzes the formation of RNA from DNA based on the nucleic acid sequence.
In the given sequence, it is instructed to use the lower strand as the templete.
a) mRNA is the complemetary strand to the templete.
The complimentary strand to the given templete is :
mRNA: 5' CGC UAU GAA UCC AAU CAA GCA UGA AUA GUU U 3'
b) Polypeptide is the polymer of aminoacids formed through the process called translation. Translation is the process by which ribosomes synthesise proteins by using the codon on mRNA.
{Amino terminal (arg - tyr - glu - ser - asn - gln - ala) Carboxy terminal } is the resultant polypeptide from the above mRNA transcript.
UGA is the stop codon. Hence translation terminates here.
c) The third amino acid of the above obtained polypeptide is glutamic acid (5' GAA 3'). The sequence of bases of anticodon is 5' UUC 3'
d) Though there are 10 codons only 7 codons are used to produce polypeptide because 8th codon is the stop codon which terminates translation process. The 7 codons are 5' CGC UAU GAA UCC AAU CAA GCA 3'
e) The tRNA molecules carrying 7 anticodons complimentary to the 7 codons on mRNA are involved in the synthesis of above polypeptide.
f and g)
UTR is the untranslated region, one on each side of the coding sequence on mRNA strand. If the UTR is found on 5' side, it is called as the leading UTR or the leader sequence. If the UTR is found on 3' side of mRNA, it is called the trailer sequence.
5' UTR is present just before the start codon AUG.
3' UTR is the codon which is present immediately after the stop codon. In the above mRNA sequence, AUA is the 3' UTR which is present immediately after the stop codon UGA.
h ) 7 tRNA molecules carrying 7 anticodons complimentary to the 7 codons on mRNA are involved in the synthesis of the above polypeptide.
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