A converging lens of focal length 25cm is placed 50cm in front of a diverging le

Question

A converging lens of focal length 25cm is placed 50cm in front of a diverging lens that has a focal length of -25cm. If an object is placed 75cm in front of the converging lens, what is the location of the final image? What is the total magnification? Is the image real or virtual?

Explanation / Answer

From 1/do + 1/di = 1/f we get 1/di = 1/25 - 1/75 => di = 37.5 and for second lens, object distance is (50-37.5) = 12.5.... 1/di = -1/25 - 1/12.5.... di = -8.33 ... locaion of image is 8.33cm behind the diverging lens or 58.33 behind the converging lens. Magnification = -8.33/12.5 = 0.66 image is virtual

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.