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The horizontal pipe, shown in the figure (Figure 1) , has a cross-sectional area

ID: 1908363 • Letter: T

Question

The horizontal pipe, shown in the figure (Figure 1) , has a cross-sectional area of 40.000 cm^2 at the wider portions and 10cm^2 at the constriction. Water is flowing in the pipe, and the discharge from the pipe is 6.00(10^-3)meters^3/second(6.00L/s). The density of mercury is 13.6 * (10^3) kg/m^3and the density of water is 1.00 * 10^3 kg/m^3. Part A Find the flow speed at the wide portion in meters per second. Part B Find the flow speed at the narrow portion. Part C What is the pressure difference between these portions?(In Pascals) Will give the first and best rating to the person who answers in most details including all formulas, to four decimal places, and showing ALL steps. Thanks.

Explanation / Answer

Let wide area be denoted by suffix 1 and constricted area by suffix 2.

A)

Velocity = Discharge/Area

V1 = Q/A1

V1 = (6*10^-3)/(40*10^-4) = 1.5 m/s

B)

V2 = Q/A2

V2 = (6*10^-3)/(10*10^-4) = 6 m/s

C)

P1 + 1/2*V1^2 = P2 + 1/2*V2^2

(P1 - P2) = 1/2**(V2^2 - V1^2)

(P1 - P2) = 1/2*(1*10^3)*(6^2 - 1.5^2)

(P1 - P2) = 16875 Pa

Putting _mercuy*g*h = P1 - P2

13.6*10^3*9.81*h = 16875

h = 0.12648 m