hello can you please show formulas and the numbers how u used them? sorry i have
ID: 1908240 • Letter: H
Question
hello can you please show formulas and the numbers how u used them? sorry i have so many questions, i am running out of questions this week and i still dont have correct answers for this. thank u.
A mass m = 13.0 kg is pulled along a horizontal floor, with a coefficient of kinetic friction ?k = 0.08, for a distance d = 6.7 m. Then the mass is continued to be pulled up a frictionless incline that makes an angle ? = 38.0? with the horizontal. The entire time the massless rope used to pull the block is pulled parallel to the incline at an angle of ? = 38.0? (thus on the incline it is parallel to the surface) and has a tension T = 45.0 N.
the work done by tension before the block gets to the incline?== 237.58J
2) What is the work done by friction as the block slides on the flat horizontal surface? J
3) What is the speed of the block right before it begins to travel up the incline? m/s
4) How far up the incline does the block travel before coming to rest? m 5) What is the work done by gravity as it comes to rest? J
Explanation / Answer
Applying the force will cause the block to accelerate.
Horizontal force on block is 61 cos(26°) = 54.8 N
F * d = 54.8 * 7.6 = 417 J
the work done by friction as the block slides on the flat horizontal surface in J =130*.08*6.7=69.68j
work by tension=45*6.7*cos38=237.58j
Normal force N = mg - TSin38 = 13*9.81 - 45*Sin38 = 99.8 N
Friction force = *N = 0.08*99.8 = 8 N
Work done by friction force = F*d = 8*6.7 = 53.6 N
Net work done = 237.58 - 53.6 = 183.98 N
Net work done = KE stored = 1/2*mv^2
183.98 = 1/2*13*v^2
v = 5.32 m/s
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