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A 18.5 kg block of metal measuring 12.0 cm by 10.0 cm by 10.0 cm is suspended fr

ID: 1907387 • Letter: A

Question

A 18.5 kg block of metal measuring 12.0 cm by 10.0 cm by 10.0 cm is suspended from a scale and immersed in water. The 12.0 cm dimension is the vertical dimension, and the top of the block is submerged 4.85 cm below the surface of the water. (a) What are the magnitudes of the forces acting on the top and on the bottom of the block due to the surrounding water? (Use P0 = 1.0130x10^5 N/m^2.) Ftop = ______ N Fbottom = ______ N (b) What is the reading of the spring scale? _______ N

Explanation / Answer

Bouyancy : Fa = ? * V * g ? = water density = 1000 kg/m^3 V = 1200 cm^3 = 0.0012 m^3 g = 9.8 m/s^2 ------> Fa = 1850 * 0.0012 * 9.8 = 21.756 N

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