A roller coaster starts from rest at the top of an 18-m hill as shown in the fig

Question

A roller coaster starts from rest at the top of an 18-m hill as shown in the figure below. The car travels to the bottom of the hill and continues up the next hill that is 10.0 m high. How fast is the car moving at the top of the 10.0-m hill, if friction is ignored? A block of mass m is released from rest at a height R above a horizontal surface. The acceleration due to gravity is g. The block slides along the inside of a frictionless circular hoop of radius R. Find and expression that gives the speed of the mass at the bottom of the hoop.

Explanation / Answer

4. PE lost = KE gained mg(h2-h1) = 1/2 mv^2 9.8*8 = 1/2 * v^2 v = 12.52 m/s 5. PE lost = KE gained mg*R = 1/2 mv^2 v = sqrt(2gR)

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