A car at the Indianapolis-500 accelerates uniformly from the pit area, going fro

Question

A car at the Indianapolis-500 accelerates uniformly from the pit area, going from rest to 300 km/h in a semicircular arc with a radius of 198 m. Determine the tangential acceleration of the car when it is halfway through the turn, assuming constant tangential acceleration. Determine the radial acceleration of the car at this time .m/s2 If the curve were flat, what would the coefficient of static friction have to be between the tires and the roadbed to provide this acceleration with no slipping or skidding? m/s2

Explanation / Answer

At halfway: Distance traveled S = pi x R / 2 = 311 m... Tangential accel = a = V^2 / 2 x S = (83.3 m/s)^2 / 2 x 311 = 11.2 m/s^2.. Radial accel = alpha = a / R = 11.2 / 198 = 0.0565 rad/s^2.. No slip or skid means net friction = centripetal force.. (mu) m g = m V^2 / R.. (mu) = 3.58..

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