hello can you please show the steps? thank you. block sliding 2 A mass m = 15.0

Question

hello can you please show the steps? thank you. block sliding 2 A mass m = 15.0 kg rests on a frictionless table and accelerated by a spring with spring constant k = 5126.0 N/m. The floor is frictionless except for a rough patch. For this rough path, the coefficient of friction is ?k = 0.42. The mass leaves the spring at a speed v = 3.3 m/s. The work is done by the spring as it accelerates the mass is 81.68 Joules J and the spring stretched from its unstreched length 0.1785 meters 3) The mass is measured to leave the rough spot with a final speed vf = 1.7 m/s. How much work is done by friction as the mass crosses the rough spot in J and what is the length of the rough spot in m?

Explanation / Answer

W = d KE = KEf - KE i = 1/2*15*(1.7^2 - 3.3^2)=-60 J W = - friction d = - u N d = - u mg d d = W/(-umg) = 60/(0.42*15*9.81)=0.971 m

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