As shown in the figure below, two masses m1 = 4.20 kg and m2 which has a mass 75

Question

As shown in the figure below, two masses m1 = 4.20 kg and m2 which has a mass 75.0% that of m1, are attached to a cord of negligible mass which passes over a frictionless pulley also of negligible mass. If m1 and m2 start from rest, after they have each traveled a distance h = 2.40 m, use energy content to determine the following. (a) speed v of the masses m/s (b) magnitude of the tension T in the cord N

Explanation / Answer

a) m2=.75m1=3.15kg .5*m1v1^2+.5m2v1^2=m2gx+m1gh-m2g(h+x) =>v=sqrt(2gh(m1-m2)/(m1+m2)) v=2.59m/sec b)m1g-T=m1a T-m2g=m2a =>a=(m1-m2)g/(m1+m2) =1.4 m/sec^2 T=35.28N

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