1. A 10 g bullet moving 1000 m/s strikes and passes through a 2.0-kg block initi

Question

1. A 10 g bullet moving 1000 m/s strikes and passes through a 2.0-kg block initially at rest, as shown. The bullet emerges from the block with a speed of 400 m/s.

(a) How much energy was lost in the collision?

(b) Calculate the average force exerted on the block assuming that the impact time is 10-4s.

(c) To what maximum height will the block rise above its initial position?

1. A 10 g bullet moving 1000 m/s strikes and passes through a 2.0-kg block initially at rest, as shown. The bullet emerges from the block with a speed of 400 m/s. (a) How much energy was lost in the collision? (b) Calculate the average force exerted on the block assuming that the impact time is 10-4s. (c) To what maximum height will the block rise above its initial position?

Explanation / Answer

mv1+mv2 =mv1f + mv2f (.01kg*1000m/s)= (.01*400m/s)+(2.00 * v) vf= ((.01kg*1000m/s) - (.01*400m/s))/2.0 vf= 3 m/s Max height = h = v^2/2g h =0 .46m = 46 cm

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