A block of mass m = 2.00 kg is attached to a spring of force constant k = 520 N/

Question

A block of mass m = 2.00 kg is attached to a spring of force constant k = 520 N/m as shown in the figure below. The block is pulled to a position xi = 5.05 cm to the right of equilibrium and released from rest.

(a) Find the speed the block has as it passes through equilibrium if the horizontal surface is frictionless. ____________m/s ?

(b) Find the speed the block has as it passes through equilibrium (for the first time) if the coefficient of friction between block and surface is ?k = 0.350. uk= 0.350. ______________m/s ?

Explanation / Answer

a.)
conservation of mechanical energy
=> 0+(1/2)kx^2 = 1/2 mv^2 + 0

velocity at equilibrium is calculated by
v^2 = 520(5.05/100)^2/2
v = 0.8142 m/s

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