1. Starting from an initial velocity of 0 m/s, the crazy balloon guy\'s (hereaft
ID: 1902518 • Letter: 1
Question
1. Starting from an initial velocity of 0 m/s, the crazy balloon guy's (hereafter CBG) top speed was 372 m/s. How long does it take a falling object to get to 372 m/s?2. How far did CBG fall as he got up to his maximum speed of 372 m/s? Hint: you may need to use your answer from number one.
3. Once CBG hit 372 m/s, he slowed down until he eventually came to rest (i.e. stopped moving) on the ground. This process took about 9 minutes and 30 seconds. What was CBG's average acceleration over this time. Express your answer in meters/second^2
4. CBG jumped out of a balloon 39,000 meters above the ground. Without any parachute or air resistance, how long would it take an object to fall from that height to the ground?
5. This one is challenging - how far did CBG fall between t = 11 seconds and t=12 seconds?
Explanation / Answer
1.t= sqrt(2v/g) = 8.71 seconds. 2. d= 1/2at^2 = 371.73 meters 3.average acceleration = final velocity - initial velocity / total time = 0 - 372 / 570 = -0.65 m/s^2 4.t= sqrt(2as) = 874.29 sec. 5. s1 - s2 = 1/2 a ( t2^2 - t1^2) = 112.7 meters.
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