You are using detectors that track the motion of charged particles. After one pa

Question

You are using detectors that track the motion of charged particles. After one particular collision, event 1, you observe events 2 and 3 which must be decays of neutral particles because you do not observe a particle travel to the location at which these events occur. you only observe a positively and negatively charged
particle travel away from those locations. For events 1 and 2 you measure delta t(2,1)=5 meters, delta x(2,1)=1, delta y(2,1)=2 and delta z(2,1)=2. For events 1 and 3 you measure delta t(3,1)= 4, delta x(3,1)= 3, delta y(3,1)=2 and delta z(3,1)=2. Could the particle that decays at event 2 have been created by the collision event 1? What about the particle that decays at even 3? Show work

Explanation / Answer

i) r = (1*1+2*2+2*2)^0.5 = 3 m >>>>>>>>>>>>>>>> t = 5/c >>>>>>>>>>>>>>>> v = r/t = 3/(5/c) = 3/5 c = 0.6 c >>>>>>>>>>>>>>>> v is lower than c >>>>> Yes, the particle that decays at event 2 can be created by the collision event 1. >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> ii) r = (3*3+2*2+2*2)^0.5 = 4.123 m >>>>>>>>>>>>>>>> t = 4/c >>>>>>>>>>>>>>>> v = r/t = 4.123/(4/c) = 3/5 c = 1.03 c >>>>>>>>>>>>>>>> v is greater than c >>>>> NO, the particle that decays at event 3 can NOT be created by the collision event 1.

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