(a) Determine the electric flux through this area when the electric field is per

Question

(a) Determine the electric flux through this area when the electric field is perpendicular to the surface.
1 N ? m2/C

(b) Determine the electric flux through this area when the electric field is parallel to the surface.
2 N ? m2/C

Explanation / Answer

electric flux through this area = phi (e) = dot product of electric field vector and normal area vector phi (e) = E (dot) dS phi (e) = |E|* |ds| cos ? where (?) is the angle, E vector makes with normal area vector 1) when electric field is perpendicular to the surface ? =0 {if roof is surface, then an arrow from floor through roof is the area vector >> when E is also from floor through roof, E is perpendicular to crossetion of area >> or parallel to area vector phi (e) = 5.55*10^5* 2.90 cos o = 16.095*10^5 (N-m^2/C) 1) when electric field is parallel to the surface ? = 90 deg E parallel to crosection of surface E and area vector become perpendicular no flux passes through phi (e) = 5.55*10^5* 2.90 cos 90 = 0

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