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In vacuum, the wavelength of an electromagnetic wave varies inversely with frequ

ID: 1899450 • Letter: I

Question

In vacuum, the wavelength of an electromagnetic wave varies inversely with frequency. From equation (2.24), how does the wavelength of an electromagnetic wave penetrating a conductor vary with frequency? What is this wavelength if the skin depth at this frequency is 20 nm?

Explanation / Answer

( ilde{k} = 2pi/ ilde{lambda} = pm sqrt{i omega mu_o sigma}) ( ilde{lambda} =pm rac{2pi}{mu_o sigma omega} (1- i) ) =>(lambda = pm rac{2pi}{mu_o sigma omega} propto pm rac{1}{omega} ) so (lambda) decreases with increase in (omega). ( ilde{lambda} = pm sqrt{-2 pi^2 i} cdot S) ( ilde{lambda} = pm sqrt{2pi^2} cdot S cdot (1 - i) ) or (lambda = Re( ilde{lambda}) = pm sqrt{2pi^2} cdot S ) so (lambda) decreases with increase of the Skin depth. for S = 20 nm (lambda = 88.85766 nm )

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