Teeing Off A golf club has a lightweight flexible shaft with a heavy block of wo

Question

Teeing Off A golf club has a lightweight flexible shaft with a heavy block of wood or metal (called the head of the club) at the end. A golfer making a long shot off the tee uses a driver, a club whose 300g head is much more massive than the 46g ball it will hit. The golfer swings the driver so that the club head is moving at 41m/s just before it collides with the ball. The collision is so rapid that it can be treated as the collision of a moving 300g mass (the club head) with a stationary 46g mass (the ball); the shaft of the club and the golfer can be ignored. The collision takes 7.2ms , and the ball leaves the tee with a speed of 71m/s .

If we define the kinetic energy of the club head before the collision as "what you paid" and the kinetic energy of the ball immediately after as "what you get," what is the efficiency of this energy transfer?

This is what i got so far
-change in momentum during collision = 3.3kg m/s^2
-speed of club after collsion= 30m/s
can't figure out how to find efficiency

Explanation / Answer

KE of ball after collision = 0.5 m v2 = 115.943 J

Initial Total KE before collision = 0.5 m v2 = 252.15 J

Efficiency of energy transfer to the ball = KE of ball/ Initial KE = 0.4598 0.46

46% of energy is transfered fro club to ball.

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