The gist of the problem. Puck 1 of mass (m1=.1 kg) comes in at velocity v0. It h

Question

The gist of the problem. Puck 1 of mass (m1=.1 kg) comes in at velocity v0. It hits puck 2 at rest (m2=.2 kg). Puck 1 gets deflected at an angle of 30 degrees north of the horizontal. Puck 2 gets deflected at an angle theta south of the horizontal. (collision looks like a sideways "Y"). What is the recoil speed and angle of puck 2?

Momentum Conservation in x-direction

m1v0 = m2v2cos(theta)+m1v1cos(30)

Momentum Conservation in y-direction

m2v2sin(theta) = m1v1sin(30)

Kinetic Energy Conservation

.5m1*v0^2 = .5m1v1^2+.5m2*v2^2

I'll spare the algebra but I solved for v2sin(theta) and v2cos(theta) for the mom. formulas
Then I squared them, and added them together, plugged v2^2 into the Kinetic Energy formula
and got..

V0^2 = (3/2)v1^2+(sqrt(3)/2)*v0*v1

Explanation / Answer

you did not ask to do anything , do you want to see if it is correct? Every thing you have done is good, no errors.. And recoil velocity means v1 here

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