A thermodynamic system is taken from state a to state c in the figure below alon
ID: 1896034 • Letter: A
Question
A thermodynamic system is taken from state a to state c in the figure below along either path abc or path adc. Along path abc the work W done by the system is 450 J. Along path adc, W is 120 J. The internal energies of each of the four states shown in the figure are Ua = 150 J, Ub = 240 J, Uc = 685 J, and Ud = 355 J. Calculate the heat flow Q for each of the four processes ab, bc, ad, and dc. In each process, does the system absorb or liberate heat?
Q=J absorbliberate
Processbc
Q=J absorbliberate
Processad
Q=J absorbliberate
Processdc
Q=J absorbliberate
Explanation / Answer
Q = U + W
Process ab
V is constant , W = 0
Q =U = Ub - Ua = 240-150 = 90 J : absorbed
Process bc
Q = (Uc-Ub) +W = (685-240)+450 = 895 J : absorbed
Process ad
Q = (Ud-Ua) +W = (355-150)+120 = 325 J : absorbed
Process dc
V is constant , W = 0
Q = (Uc-Ud) = (685-355) =330 J : absorbed
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