A battery of emf 10V and r = 1 ohm is connected to a resistance R = 4 ohm. Deter

Question

A battery of emf 10V and r = 1 ohm is connected to a resistance R = 4 ohm. Determine I in the circuit The potential drop in the internal resistance (r) and also the 4 ohm resistor. The terminal voltage of the battery The reading of a voltmeter connected across the battery terminals in open circuit. In the figure, the circuit is grounded at point at b and c relative to ground. Find I in circuit Arbitrarily choose the potential at a as 0V and find the relative potential at b and c Determine the pd between a and b, b and c, c and a

Explanation / Answer

Total resistance of the circuit = 0.4+0.1+2.5 = 3 ohm Effective potential in clockwise direction is positive, V = 25-10 = 15 V Hence, I in circuit = 15 / 3 = 5 A Point a is potential 0. At point b, potential = 25 - 5 * 0.4 = 23 V At point c, potential = 23 - 10 - 5 * 0.1 = 12.5 V Pd between a and b = Pb - Pa = 23 - 0 = 23 V Pd between b and c = Pc - Pb = 12.5 - 23 = -10.5 V Pd between c and a = Pa - Pc = 0 + 10.5 = 10.5 V

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