Dr. Fahrad has been riding his bike to his job and is curious how many ATP his b

Question

Dr. Fahrad has been riding his bike to his job and is curious how many ATP his body is breaking apart in order to do the work required to get to his job. Dr. Fahrad rides 8.9 kilometers to his job, has a mass of 67.2 kilograms and has an average acceleration of 1.8 kilometers per second squared ATP is able to do work, measured in kilojoules per mole of ATP broken into ADP. The SI unit for work is a joule. Using the information given we can The calculate work and then convert to moles of ATP The first step is to take stock of what we are given in the word problem and what we are trying to find. We have mass, distance, and average acceleration We are trying to find how many ATP are required to power the bike ride to work distance. However, the distance was reported in kilometers and the SI unit of distance is the meter. It is necessary to convert to meters before using this equation. W=Fd The equation for Force is mass times acceleration. This will incorporate our remaining two variables, mass and acceleration. Again, the information given to us was in km-s 2 but the SI unit for acceleration is m-s2. It is necessary to convert to m-s2 before substituting into the equation. By substituting the equation for F into the equation for W, we can figure out how many joules Dr. Fahrrad is burning on his ride to his job. In order to use these equations, we are assuming quite a few things. Below are some of the assumptions . no friction . no mass of the bike . a flat ride with no change in altitude This perform the conversion above will calculate work in joules. The conversion factor jor swtching between ATP and work is given in kilojoules. The units must match to correctly The last step is to conyert work calculatedin oules, into moes of ATP being broken required to do the work. If we assume standard temperature and pressure the breakdown of a mole of ATP releases 29 kilojoules available to do work How many moles of ATP is Dr. Farhad breakdown to get to work? Report your answer to one decimal place

Explanation / Answer

Given data :

m = 67.2 Kilograms, a = 1.8km/s2 = 1800m/s2 , d = 8.9 km = 8900 metres, Energy gained from one ATP when ATP is broken down to ADP is 29 Kilojoules.

F = m.a = 67.2 X 1800 N

W = F.d = m.a.d = 67.2 X 1800 X 8900 = 1076544000 Joules = 1076544 Kilojoules

Amount of ATP required = 1076544 / Energy gain from one ATP ( in Kilojoules) = 1076544 / 29 =37122.2 ATPs.

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