Quiz 1. CHEG 3550 Spring 2017 You are studying an enzyme reaction using an enaym
ID: 189476 • Letter: Q
Question
Quiz 1. CHEG 3550 Spring 2017 You are studying an enzyme reaction using an enayme preparation at low (A) and high (B) substrate Feb. 15, 3027 Closed book and closed notes. Ony caliculator, pencil, brain, and Reference Info on neverse side of th Chart A Chart B D.0918x+0.7827 R 0.9971 02 1. (4pts) What is V and Ku from chart A above? Include Units. 2. (4pts) What is V, and K from chart 8 above? Include Units (ipoint each for correct answer and correct units) A.55 3. (2 points)Hypothesize what is causing the V and Kw values from the two charts to be different. This is not in your textbook. You will have to think! Assume you have done everything correctly and Michaelis/Menton kineties are being followed. nffect the veectienExplanation / Answer
As y=mx+C
y=0.218x + 0.5037
y intercept = 1 / Vmax
1/vmax = 1/0.5037
= 1.985 mol/sec
Km= 1.985*.218
= 0.432
2. From the Lineweaver burk plot
As y=mx+C
y=0.0918x+ 0.7827
1/vmax = 1/0.7827
=1.277 mol/sec
Km= 1.277*.0918
= 0.025
3. Vmax stands for maximum velocity attained by an enzyme and Km stands for Michaelis constant. In both the graph , the substrate concentration is different, Hence we obtain two values of Vmax and Km.
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