A 975 kg two-stage rocket is traveling at a speed of 5.80 x 10^3m/s with respect

Question

A 975 kg two-stage rocket is traveling at a speed of 5.80 x 10^3m/s with respect to the Earth when a pre-designed explosion separates the rocket into two secions of equal mass that then move at a speed of 2.20 x 10^3 m/s relative to each other along the original line of motion.
A. What are the speed and diretion of each section (relative to the Earth) after the explosion?
B. How much energy was supplied by the explosion?
[Hint: What is the change in KE as a result of the explosion?]
Can someone please explain in detail what to do, and not just copy it off of another website, because i dont understand. Also is there any other way to do it then do the v1-v2=vrel thing because i dont understand that

Explanation / Answer

by momentum conservation 975 *5.8*10^3 = 975/2 (v + (v+2.2*10^3)) therefore v= 4.7 *10^3 m/s and the velocity of another part = 6.9*10^3 and there direction will remain same as the initial direction of the rocket B) change in kinetic energy 1/2 *975/2 *((4.7 *10^3)^2 +(6.9*10^3)^2 ) - 1/2 *975 *(5.8*10^3)^2 =589875000 J

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