1) N=39062500 2) N=19531250 3) N=9765625 4) N=3906250 I don\'t believe this is r
ID: 188745 • Letter: 1
Question
1) N=39062500
2) N=19531250
3) N=9765625
4) N=3906250
I don't believe this is right but I just used the value of N at year 10 and divided it by lambda to solve for N0.
Explanation / Answer
1) given that, Nt = N0*()t
where, N0 = 2, = 0.5 and t = 10 yrs
therefore, Nt = 2 * (0.5)10 = 2 * 0.0009765625 = 0.0019531250
2) = 1
N10 = 2 * (1)10 = 2
3) = 2
N10 = 2 * 210 = 2 * 1024 =2048
4) = 5
N10 = 2 * 510 = 2 * 9765625 = 19531250
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.