value 10.00 points 1 out of 3 attempts Ass Starting with the left-most column, p
ID: 1886327 • Letter: V
Question
value 10.00 points 1 out of 3 attempts Ass Starting with the left-most column, populate the boxes from left to right without skipping empty boxes. Ties should be grouped in the same box. Rank the maximum possible forces of static friction, from smallest to largest, between the groups of boxes and the inclined surfaces for the following arrangements of boxes. Each box has identical mass and coefficient of static friction, g, with respect to the surface of the incline. You may assume that all of the boxes are at rest and do not slide and that stacked boxes will not topple. A. B. C. 24° 46° 41 D. E. 15°
Explanation / Answer
boxes are at rest.
so along the incline,
F_net = fs - M g sin(theta) = 0
fsA = (4 m g )sin24 = 1.63 m g
fsB = (4 m g )sin46 = 2.88 m g
fsC = (4 m g)sin41 = 2.62 m g
fsD = (4 m g )sin0 = 0
fsE = (4 m g)sin15 = 1.04 m g
D < E < A < C < B
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