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Question

s Animations Slide Show Review View · Shapes. Convert toPicture Text BoxArrange Quick Styles 4 Unpolarized light with intensity S is incident on a series of polarizing sheets The first sheet has its transmission axis oriented at 0°. A second polarizer has its transmission axis oriented at 45° and a third polarizer oriented with its axis at 90. Determine the fraction of light intensity exiting the third sheet with and without the second sheet present a) 0.5S, S b) 0.5S, zero c) 0.25S, zero d) 0.25s, 0.5s e) S,0.5s · HTIJ

Explanation / Answer

As Unpolarised light passes through polarizer,its intensity halved and it get polarized along the axis.

S1 = S/2

and after that Sf = Si (cos(theta)^2 )

S2 = S1 (cos45)^2 and S3 = S2(cos45)^2

S3 = (S/2)(cos45)^4 = 0.125 S (with middle sheet)

when 2nd sheet is removed.

then from 1 to 3: theta = 90 deg

cos90 = 0

final S = 0

Ans: 0.125S, zero

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