A parallel plate capacitor (two oppositely charged conducting plates arranged pa

Question

A parallel plate capacitor (two oppositely charged conducting plates arranged parallel to each other) has its positive plate with charge +Q on the left and its negative plate (charge -Q) on the right. Assume the gap between the plate is small compared to the length of the plates. You measure the electric field in the gap as you move from the positive to negative plate. What is true? Assume you are far from the edges of the plates. O The E field is the same everywhere in the gap and points to the left O The E field decreases as you reach the middle of the gap and then increases again as you reach the other plate. The E field points to the left the whole time. The E field decreases as you reach the middle of the gap and then increases again as you reach the other plate. The E field points to the right the whole time. The E field is the same everywhere in the gap and points to the right.

Explanation / Answer

the field will be same everywhere if the gap is small compared to the dimesnions of the plates.

The field will be from positive plate to the negative plate. So field is same everywhere and is directed to the right.

Hence the correct option is the last one.

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