I ONLY NEED HELP WITH PART C. INCORRECT ANSWERS: 90.36 J/s and 39.63 J/s PART A
ID: 1885847 • Letter: I
Question
I ONLY NEED HELP WITH PART C.
INCORRECT ANSWERS: 90.36 J/s and 39.63 J/s
PART A FORMULA: Q=mLv => 0.0000385kg x 2430000J/kg = 93.56 J/breath
PART B FORMULA: Q/t = 93.56J/breath x 18breaths/min x 1min/60sec = 28.07J/s
(5%) Problem 22: Suppose a person inhales and exhales 1.85 L of 37.0°C air Substances Specific heat (c) Solids evaporating 3.85 x 102 g of water from the lungs and breathing passages with each breath J/kg-C 840 840 3500 2090 kcal/kg. C Concrete (Granite) Glass Human Body Ice (average) 0.20 0,20 0.83 0.50 Liquids Water 4186 1.000 Gases Air (Dry) Steam (100 C) 721 (1015) 0.172 (0.242 1520 (2020) 0.363(0.482) Otheexpertta.com 33% Part (a) How much heat transfer, in joules, occurs due to evaporation in each breath? The latent heat of vaporization of water is LV-2430 kJ/kg Q = 93.56 V Correct! O 33% Part (b) What is the rate of heat transfer, in watts, if the person is breathing at a moderate rate of 18.0 breaths per minute? Pin-28.07 Correct 33% Part (c) If the inhaled air had a temperature of 200°C, what is the rate of heat transfer, in watts, for warming the air to the body temperature of 37°C? You may assume the temperature inside a human body is a constant 37.0°C, and the density of air at this temperature is 1.20 kg/m3 out Deductions Potential 0% 100%Explanation / Answer
1.85 L air = (1.20 kg / m^3)(1.85 x 10^-3 m^3)
m = 2.22 x 10^-3 kg per breath
Q = m C deltaT
Q = (2.22 x 10^-3 kg)(721 J / kg deg C )(37- 20)
Q = 27.2 J per breath
time for 1 breath, t = 60 sec / 18 = 3.33 s
P = Q/t = 8.16 W
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