Learning Gosl: To practice Problem Sching Strutgy 21.2 Electric-Field Colculatio

Question

Learning Gosl: To practice Problem Sching Strutgy 21.2 Electric-Field Colculations 0,0 Find the and yenants ot tha Intal alacric located on the x adsata- 6.00 cm and Fy at point P, wich is Correct Ihe scurce points are the three pcint charges alang the y ads, repnesanting whare the elecric tield emanates The teld palnt Is located at point P, and repeecents the location whre you wil need to EXECUTE the solution as follows Part B Find the x and y components of the 10tal cloctric fied at point P. which is located cn the K 0s at-6.00 cm Vinw Available Hinn) Figure 1 of1 ? 1 Submit Roquest Answer EVALUATE yuur answer Part C Complete previous parl(s) Next >

Explanation / Answer

We know that electric field at a point is given by:

E = k*Q/r^2, where r = distance between charge and point

Direction of electric field at point is towards the negative charge and away from positive charge, So from this we can see that: due to q2 direction will be towards east, due to q1 direction will be south of east and due to q3 direction will be north of east.

Now electric field due to q2 will be

E2 = k*q2/r2^2

q2 = 4.50 nC, r2 = 6 cm = 0.06 m, So

E2 = 9*10^9*4.5*10^-9/0.06^2 = 11250 N/C

E2x = 11250 N/C

E2y = 0 N/C

Now electric field due to q1 will be

E1 = k*q1/r1^2

q1 = 4.50 nC, r1 = sqrt (6^2 + 8^2) cm =10 cm = 0.1 m, So

E1 = 9*10^9*4.5*10^-9/0.1^2 = 4050 N/C

Now we can see that electric field will be in south of east,(4th quadrent)

E1x = E1*cos A = 4050*(0.06/0.1) = 2430 N/C

E1y = -E1*sin A = -4050*(0.08/0.1) = -3240 N/C

Now electric field due to q3 will be

E3 = k*q3/r3^2

q3 = 4.50 nC, r3 = sqrt (6^2 + 8^2) cm =10 cm = 0.1 m, So

E3 = 9*10^9*4.5*10^-9/0.1^2 = 4050 N/C

Now we can see that electric field will be in north of east,(1st quadrent)

E3x = E3*cos A = 4050*(0.06/0.1) = 2430 N/C

E3y = E3*sin A = 4050*(0.08/0.1) = 3240 N/C

SO net electric field will be

Ex = E1x + E2x + E3x = 2430 + 11250 + 2430

Ex = 16110 N/C

Ey = E1y + E2y + E3y = -3240 + 0 + 3240

Ey = 0 N/C

So,

Ex, Ey = (16110, 0) N/C

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