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any help would be great! piesented in Figure 9.1 FIRST REQUIREMENT Complete the

ID: 1885565 • Letter: A

Question

any help would be great!

piesented in Figure 9.1 FIRST REQUIREMENT Complete the following material balance table and answer the ques- tions that follow. Some additional data are given as follows: fuel oil specific gravity 0.90 fuel oil composition (weight percent): C 88%; H 11.7%; s 0.3% kiln particulate emissions-: 5.0% of dry solids feed rate combustion air supplied per kg of fuel 18 kg/kg auxiliary air supplied per kg of moist solids feed 0.30 kg/kg inlet air composition (mole percent): N2-78%; 02 21%; Material Balance Table Cornponent, thousand kghr Stream Number Dry Solids Nz O2 CO2 H2O S Other Total 0 0 0 4.17 0 0 4.00 0 52.0 50.0 46.0 0 4 0 Questions 1. Calculate the mass emission rate of particles from the dryer, 2. Calculate the percentages of the raw feed that are lost in 3. Calculate the mass emission rate of SO2 from the dryer, in 4. Calculate the concentration of particles emitted from the 5. Calculate the concentration of So2 in the exhaust, in 6. If emissions limits require that less than 30 kg/hr of particles in kg/hr. the crushing step and in the drying step. kg/hr. dryer, in ug/std m Hg/std m3 and in ppm.

Explanation / Answer

1.) Mass emission rate of particles from the dryer: 52 - 4.17 = 47.83 kg/hr

2.) 100 % of raw feed is lost in crushing and drying step.

3.) Mass emission rate of SO2 from dryer is: 0.9 * (6000/1000) * 52 * 0.003 = 0.8424 kg/hr

4.) Inlet air: wt %: N2 = (0.78*28)/(0.78*28+0.21*32+0.01*40) = 0.754,

O2 = (0.21*32)/(0.78*28+0.21*32+0.01*40) = 0.232,

Ar = (0.1*40)/(0.78*28+0.21*32+0.01*40) = 0.014

Feed rate: Total = 18*52 = 936 kg/hr

N2 = 0.754*18*52 = 705.744 kg/hr,

O2 = 0.754*18*52 = 217.152 kg/hr

Ar = 0.014 * 18 * 52 = 13.104 kg/hr