Your answer is partially correct. Try again. Interactive LearningWare 18.2 provi

Question

Your answer is partially correct. Try again. Interactive LearningWare 18.2 provides one approach to solving problems such as this one. The drawing shows three point charges fixed in place. The charge at the coordinate origin has a value of q-+6.45 C; the other two have identical magnitudes, but opposite signs: 02- -5.57/C and Q, - +5.57HC. (a) Determine the net force exerted on q, by the other two charges. (b) If q, had a mass of 1.50 g and it were free to move, what would be its acceleration? 1.30?" 1.30m (a) Number?1.0656 (b) Number Click if you would like to Show Work for this question: Oen Show Wonk SHOW HINT LINK TO TEXT e to search

Explanation / Answer

Electric force due to q2

F2= 9*10^9*6.45*10^-6*5.57*10^-6/(1.3^2)* ( cos 23 i + sin 23 j)

F2= 0.176 i + 0.0748 j

Similarly, Electric force due to q3

F3= - 0.176 i + 0.0748 j

Net force,

F= F1+F2= 2*0.0748= 0.1496 N

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ma= 0.1496

1.5*10^-3*a= 0.1496

a= 99.733 m/s^2

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Plz post other problems seperately

Comment in case any doubt.. good luck

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