Please show all work and be careful of the charges Three point charges are arran

Question

Please show all work and be careful of the charges

Three point charges are arranged in a horizontal line as shown below. Find the electric force on Q1 given the following: Q1 =-1 mC, Q2 =-3 mc, Q3 =-3 mc, r1 = 90 m, and r2 180 m. Remember that a positive force points to the right and a negative force points to the left. Q, Q2 Q3 What is the net force on charge Q1? 3.70 (in units of N) Computer's answer now shown above. Incorrect. Tries 3/3 Previous Tries What is the net force on charge Q2? (in units of N) The total force on Q2 is going to be a vector sum of F21 (the force on Q2 due to Q1) and F23 (the force on Q2 due to Q3). You need to find both the magnitudes and directions of F21 and F23- The magnitudes of the forces are given by: F21 kQ2Q1/r1 and F23 kQ203/r22 where k 9e9 Vm/C and the absolute values for all charges should be used The direction of each force is determined by the two charges, where opposite charges attract and same charges repel Submit Answer Incorrect. Tries 2/3 Previous Tries What is the net force on charge Q3? (in units of N) Submit Answer Tries 0/3 What is the sum of the forces on all three charges? (in units of N) Submit Answer Tries 0/3

Explanation / Answer

Given,

Charges, Q1 = - 1 mC, Q2 = - 3 mC, Q3 = - 3 mC

Distance, r1 = 90 m, r2 = 180 m

A)

Force on Charge 1, F1 = net force on Q1 due to Q2 and Q3

F1 = -([ k Q1 Q2 / r1^2 ] + [ k Q1 Q3/(r1+r2)^2 ])

= -( [ 9 x 10^9 x 10^-3 x 3 x 10^-3/ (90)^2] + [9 x 10^9 x 10^-3 x 3 x 10^-3 / (270)^2 ])

= - 3.7 N

B)

F2 = net force on Q2 due to Q1 and Q3

F2 = + [ k Q2 Q1/r1^2 ] - [ k Q2 Q3/(r2)^2 ]

F2 = (9 x 10^9 x 10^-3 x 3 x 10^-3/90^2) - ( 9 x 10^9 x 3 x 10^-3 x 3 x 10^-3 / 180^2 )

= 0.833 N

C)

F3 = net force on Q3 due to Q1 and Q2

F3 = [ k Q3 Q1/(r1+r2)^2 ] + [ k Q3 Q2/ r2^2 ]

= [9 x 10^9 x 10^-3 x 3 x 10^-3 / 270^2 ] +[ 9 x 10^9 x 3 x 10^-3 x 3 x 10^-3 / 180^2 ]

= 2.87 N

D)

sum of all forces = F1 +F2 +F3 = 0

Comment in case any doubt please rate my answer ....

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