Question 5 FIGURE 4-11 S0N/y 6.0N The free-body diagram of an 8.00 kg object is

Question

Question 5 FIGURE 4-11 S0N/y 6.0N The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? 0 (6 O N cos 28. + 5.0 N cos 22"X + (6 0 N sin 28. + 5 0 N sin 22°) = (8 00 kg); O (6 O N cos 28. . 50 N sin 22°); + (6 0 N sin 28" + 5 0 N cos 22°)-(8 00 kg): (6 ON cos 28" + 5 0 N sin 22°); + (6 0 N sin 28" . 5.0 N cos 22°)^ = (8.00 kg) 0 (6 0 N cos 28"-50Ncos 22"); + (6 0 N sin 28" + 5 0 N sin 22 =(8 00 kg): O (6.0 N sin 28-5.0 N sin 22) (60 N cos 28+50 N cos 22 (800 kg)

Explanation / Answer

The horizontal component of both the forces will be in opposite direction while component of force in y direction for both forces will have same direction so 4th option is correct.

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