0/10 points Previous Answers SerPSET9 28.P019. Calculate the power delivered to

Question

0/10 points Previous Answers SerPSET9 28.P019. Calculate the power delivered to each resistor in the circuit shown in the figure below. (Let Ri-5.00 , R2-2.00 , and V-21.0 V) If you replace all four resistors with an equivalent resistance, would this affect the current through the battery? How is the current battery related to the current through R,?W 22.5 resistor R 1 4.00-ohm resistor resistor R2 1.00-ohm resistor 4.04 across resistor R279 How does the potential difference across the 1.00- resistor compare to the potential difference R2 1.0011 4.00 Dw

Explanation / Answer

R2 and 1 ohm are parallel Hence the effective resistance is ( 2x1/(2+1)) = 2/3 ohm

Now R1 , 2/3 ohm and 4 ohm are in series

Hence the toal resistance is 5 + (2/3) + 4 = 29/3 ohm

Hence the total current in the circuit is I = V/R = 21 / (29/3) = 2.17 A

Now voltage drop across 5 ohm is V1 = IR = ( 2.17) ( 5 ) = 10.85 V

Hence power is P = IV1 = (2.17) (10.85) = 23.54 W

Voltage drop across the parallel combination is V2 = (2.17)(2/3) = 1.44 V

Hence current across R2 is I2 = V2/R2 = 1.44/2 = 0.72 A

Hence Power across R2 is P = I2V2 = (0.72) (1.44) = 1.0368 W

Current across 1 ohm is I3 = V2/1 = 1.44/1 = 1.44 A

Hence power acorss 1 ohm is P = (1.44A) (1.44 V) = 2.0736 W

Voltage drop across 4 ohm is V3 = I/4 = 2.17 /4 = 0.5425 V

Hence Power across 4 ohm is P = V3 I = (0.5425) (2.17) = 1.177 W

Since 1 ohm and R2 are in parallel, both will have same potential difference across them.

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