What is the direction of the electric field? What is the magnitude of the electr
ID: 1883620 • Letter: W
Question
What is the direction of the electric field?
What is the magnitude of the electric field at z0. (N/C) ?
At large distances from the circle, what is the size of the dipole moment? (C*m) p -->
Explanation / Answer
Firstly we find direction of An electric field is generated by electric charge and tells us the force per unit charge at all locations in space around a charge distribution The electric field extends out into space around the charge distribution The electric field exerts a force on the test charge in a given direction. The force exerted is proportional to the charge of the test charge electric field is “the force per unit charge” is written as
E=Fqtest
E=Fqtest
where we are considering only electric forces. Note that the electric field is a vector field that points in the same direction as the force on the positive test charge. The units of electric field are N/C. Then we find the magnitude Now consider the magnitude of the force between this point charge Q and the test charge is given by Coulomb’s law:
F=k|Qqtest|r2
F=k| Qqtest |r2
where the absolute value is used since we only consider the magnitude of the force. The magnitude of the electric field is then.
E=Fqtest=k|Q|r2 This equation gives the magnitude of the electric field created by a point charge Q. The distance r in the denominator is the distance from the point charge Q (or from the center of a spherical charge) to the point of interest. We know thatThe larger the difference in electronegativity, the larger the dipole moment. The distance between the charge separation is also a deciding factor into the size of the dipole moment. The dipole moment is a measure of the polarity of the molecule.
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