#13-17 13. Two masses are attached via ropes and are free to slide on a friction

Question

#13-17 13. Two masses are attached via ropes and are free to slide on a frictionless table. Mark pulls the force "F" such that the meter "B" reads 84 N. What does meter "A" read? 3kg A 4kgBF a, 0 b. 36 . 48 e. none of these e. none of these e. none of these d. 84 14. If we now include friction, with H 0.2, then the frictional force on the 4 kg mass would be, 15. With this friction, with Mark still pulling with the same force F as before, meter "B" now reads, 17. In this room, your book drops with acceleration "g". If the mass of the earth was doubled (but the size a. 16.8 N a. 84 N kept the same), and we used a book with double the mass, the dropping acceleration would be b. 14 N c. 8 N d. 0 b. 14 N C. 8N d. 0 a. "g" b. "2g" c. "4g" d. "g/2" e. none of these

Explanation / Answer

13)

for 3 kg mass

Fnet = m*a

A = 3*a

for 4 kg mass

Fnet = m*a

B - A = *a

84 - 3*a = 4*a

accelration a = 84/7 = 12 m/s^2

A = 3*12 = 36 <<<-------------ANSWER

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14)

frictional force f = u*4*g = 0.2*4*10 = 8 <<-----answer

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15)

B = F = 84 N

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17)

Force F1 = G*ME*m1/R^2

a1 = F1/m1 = G*ME/R1^2 = g

for m2 = 2*m1

R2 = R1

F2 = G*2*ME*2*m1/R1^2

F2 = 4*G*ME*m1/R1^2 = 4*F1

a2 = F2/m2 = 4*F1/(2*m1) = 2*(F1/m1) = 2g

OPTION " b "

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