(10%) Problem 5: A projectile is launched at ground level with an initial speed
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Question
(10%) Problem 5: A projectile is launched at ground level with an initial speed of 196 fts, at an angle of 29° above the horizontal. It strikes a target above the ground 3.4 seconds later w o 50% Part (a) what is the honzontal distance, in feet from where the projectile was launched to where it lands? x=582 B Correct ! 50% Part (b) what is the vertical distance, in feet, from where the projectile was launched to where it lands? Deductions Petential sin COS0 tan07 8 cotan si acos0) Submissioms Amempes remaining 4 5 6 1 2 3 atan) acotan sinho cosh tanh0 cotanho e Degrees Radians Sabmit feedbackI give up!Explanation / Answer
given
vo = 196 ft/s
vox = 196*cos(29) = 171 ft/s
voy = 196*sin(29) = 95 ft/s
we know, g = 9.8 m/s^2
= 9.8/0.3048 ft/s^2
= 32.1 ft/s^2
a) horizontal distance travelled,
x = vox*t
= 171*3.4
= 581.4 m
b) vertical distance travelled,
y = voy*t + (1/2)*(-g)*t^2
= 95*3.4 + (1/2)*(-32.1)3.4^2
= 137.5 m <<<<<<<<<<-------------Answer
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