top of left hand cf 122 7 top of right hand ci -9.8 bottom of canyon +a(m) Show
ID: 1883095 • Letter: T
Question
top of left hand cf 122 7 top of right hand ci -9.8 bottom of canyon +a(m) Show and explain all your work for complete (or possible partiall ) credit-just having the right answer is worth very little. For every calculation you do, first show the formula you use (without numerical values), then show what numerical values you use and where they are substituted into the formula, and finally show the numerical result. Be sure to at least include the proper units in the final numerical result. To save time, you do not (and should notj follow the sig fig rules-just keep at least 3 or 4 sig figs in your intermediate calculations and final result Physical Situation: Horizontal Acceleration 0.00 m/s Vertical Acceleration-9.80 m/s downward Initial vertical location of the baill at top and face of right cliff Initial horizontal location of the ball at top and face x of right clif Horizontal component of the initial velocity Vertical component of the initial velocity The vertical level of the top of the left cliff The horizontal location of the face of the left cliff The vertical level of the top of the right cliff The horizontal location of the face of the right cliff x- The vertical level of the bottom canyon floor Representation in Coordinate System:Explanation / Answer
From the given diagram
2. initial velocity components
vox = -32*cos(180 - 122.7) = -17.28769 m/s
voy = 32*sin(180 - 122.7) = 26.9283450 m/s
3. initial height = 20 m
height of cliff = 50 m
when x = -30 m
vox = x/t
t = x/vox = 1.7353388451 s
height of ball at this time is y
y = 20 + voy*t - 0.5gt^2 = 51.9588 m
this is more than height oif cliff
hecne the ball will impact on the top of the cliff
4. time of impact = t
now when impact occurs y = 50 m
50 = 20 + voy*t - 0.5gt^2
4.9t^2 - 26.92834*t + 30 = 0
t = 3.9426 s
5. x coordinate = vox*t = -68.1584465 m
y coordiante = 50 m
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