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Question 8 2 pts A cosmic ray electron moves at 7.06x106 m/s perpendicular to th

ID: 1882985 • Letter: Q

Question

Question 8 2 pts A cosmic ray electron moves at 7.06x106 m/s perpendicular to the Earth's magnetic field at an altitude where field strength is 0.63x10-5T What is the radius of the circular path the electron follows? D | Question 9 2 pts A wire carrying a 22.5 A current passes between the poles of a strong magnet that is perpendicular to its field and experiences a 1.86 N force on the 3.16 cm of wire in the field. What is the average field strength? D | Question 10 2 pts A non-mechanical water meter could utilize the Hall effect by applying a magnetic field across a metal pipe and measuring the Hall voltage produced. What is the average fluid velocity in a 3.29 cm diameter pipe, if a 0.654 T field across it creates a 74.5 mV Hall voltage?

Explanation / Answer

8.

Charge particle in magnetic field

r= mv/qB= 9.1*10^-31* 7.06*10^6/(1.6*10^-19*0.63*10^-5)

r= 6.3736 m

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F = BiL

1.86= 22.5*0.0316* B

B= 2.616 T

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Plz post other problems seperately

Commemt in case any doubt.. good luck

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