for part D i also got a 5.35E12 but there was no way i could try scientific nota

Question

for part D i also got a 5.35E12 but there was no way i could try scientific notation i may have been off on my zeros but im not sure what is right / im stuck please explain

18854783#Q11 https://www.webassign.net/web/Student/Assignment Responses/submit?dep 1.512 points | Previous Answers A soft tennis ball is dropped onto a hard floor from a height of 1.75 m and rebounds to a height of 1.21 m. (Assume that the positive direction is upward.) (a) Calculate its velocity (in m/s) just before it strikes the floor 5 85 m/s (b) Calculate its velocity (in m/s) just after it leaves the floor on its way back up 4 87 m/s O) calculate its acceleration (in m/'s) during contact wth the floor f that contact lasts 3 s0 ms or if that contact lasts 3.50 ms 3060 m/s2 (d) How much (in m) did the ball compress during its collision with the floor, assuming the floor is absolutely 0187x m ditional Materials La Reading Submit Answer Save ProgressPracice Another Version 2 points 1 Previous Answers You toss a tennis ball straight upward. At the moment it leaves 12 your hand it is at a height of 1la m above the ground, and it is moving at a speed of 7.2 m/s (a) How much time does it take for the tennis ball to reach its maximum height? 73

Explanation / Answer

d)

Using 3rd equation of motion

d= u^2/(2a)

= (-5.85)^2/(2*3060)

= 5.59*10^-3 m

Or

d= 0.00559 m

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Goodluck

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