A water skier is being pulled by a boat. As she approaches a wave that is angled

Question

A water skier is being pulled by a boat. As she approaches a wave that is angled at 17.0 she reaches a constant speed of 19.0 m/s She launches off the first wave and lands on a second wave at the same height. How long was she in the air? 1.13 s 3.88s 0.567 s 3.71 s Question 3 A hang glider pilot is flying horizontally over an open field when her shoe falls off She was going 250 m/s and was 96.0 m above the ground. How long did it take for the shoe to hit the ground? 0260s 4.43 s 19.9s 2.55 s Click "Submit Answer" below to submit all 3 of your answers

Explanation / Answer

here,

2)

theta = 17 degree

constant speed , u = 19 m/s

as the Skier lands on the same height

the time for which the Skier in the air , t = time of flight

t = 2 * u * sin(theta)/g

t = 2 * 19 * sin(17) /9.81 s

t = 1.13 s

3)

height , h = 96 m

the time taken to hit the ground be t

h = 0 + 0.5 * g * t^2

96 = 0 + 0.5 * 9.81 * t^2

solving for t

t = 4.43 s

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