(490) Problem 11: While competing in the long jump, a person leaps over a smooth
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(490) Problem 11: While competing in the long jump, a person leaps over a smooth horizontal sand surface. She lands on the surface with speed vf= 9.75 ms at an angle = 3ge below horizontal. Assume that the person moves without air resistance. Use a Cartesian coordinate system with the origin at her final position. The positive x-axis is directed from her initial to her final position, and the positive y-axis is directed vertically upwards 33% Part (a) Enter an expression for the jumper's initial velocity vector in terms of vf 9, g, and the unit vectors i and j vo-(Vfcos()i(Vfsin(e))j Correct! 33% Part (b) Calculate the maximum height, in meters, that the jumper reaches above ground level. ax-1.919 /Correct! * 33% Part (c) What x position in meters, did the jumper begin her long jump? Grade Summa Deductions Potential Xo = 46.94 0% 100% sin0 cos0 cotan0asin acos0 atan0 acotan sinhO cosh0 tanh cotanh0 O Degrees Radians 78 9HOME Submissions Attempts remaining: (090 per attempt) detailed view 0% 0% 0% END BACKSPACE DEL CLEAR Submit Hint I give up!Explanation / Answer
Range= u^2 sin (2x)/g
= -9.75^2* sin sin 78/9.8
= - 9.488 m
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Comment in case any doubt.. good luck
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