Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

please answer questions 3 and 4 DI Question 3 18 pts Vector A has a magnitude of

ID: 1881554 • Letter: P

Question

please answer questions 3 and 4

DI Question 3 18 pts Vector A has a magnitude of 12 and is at 180 degrees counter-clockwise from the +x axis, vector B has a magnitude of 7 and is at 35 degrees counter-clockwise from the +x axis, vector C has a magnitude of 15 and is at 127 degrees counter-clockwise from the +x axis, and vector D has a magnitude of 6 and is at 217 degrees counter-clockwise from the +x axis. If vector R A B+C D, what is the magnitude of vector R? Question 4 18 pts Vector A has a magnitude of 19 and is at 180 degrees counter-clockwise from the +x axis, vector B has a magnitude of 6 and is at 24 degrees counter-clockwise from the +x axis, vector C has a magnitude of 13 and is at 133 degrees counter-clockwise from the +x axis, and vector D has a magnitude of 6 and is at 218 degrees counter-clockwise from the +x axis. If vector R A-B+C D, what is the angle of vector R measured counter-clockwise from the x axis in degrees? D Question 5 18 pts

Explanation / Answer

here,

3)

A = - 12 i m

B = 7 m * ( cos(35) i + sin(35) j)

B = 5.73 i m + 4.02 j m

C = 15 m * (cos(127) i m + sin(127) j m)

C = - 9.03 i m + 11.98 j m

D = 6 m * ( cos(217) i + sin(217) j)

D = - 4.79 i m - 3.61 j m

R = A- B + C - D

R = - 20.09 i m + 12.39 j m

the magnitude of R , |R| = sqrt(20.09^2 + 12.39^2)

|R| = 23.6 m

4)

A = - 19 i m

B = 6 m * ( cos(24) i + sin(24) j)

B = 5.48 i m + 2.44 j m

C = 13 m * (cos(133) i m + sin(133) j m)

C = - 8.87 i m + 9.51 j m

D = 6 m * ( cos(218) i + sin(218) j)

D = - 4.73 i m - 3.69 j m

R = A- B + C - D

R = - 27.12 i m + 8.26 j m

the magnitude of R , |R| = sqrt(27.12^2 + 8.26^2)

|R| = 28.3 m